131141252000 has 144 divisors (see below), whose sum is σ = 354170476296. Its totient is φ = 47687552000.

The previous prime is 131141251991. The next prime is 131141252003. The reversal of 131141252000 is 252141131.

It can be written as a sum of positive squares in 4 ways, for example, as 7144306576 + 123996945424 = 84524^2 + 352132^2 .

It is a super-2 number, since 2×131141252000² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is not an unprimeable number, because it can be changed into a prime (131141252003) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 348524 + ... + 619476.

Almost surely, 2^131141252000 is an apocalyptic number.

131141252000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131141252000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (177085238148).

131141252000 is an abundant number, since it is smaller than the sum of its proper divisors (223029224296).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131141252000 is a wasteful number, since it uses less digits than its factorization.

131141252000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 271000 (or 270971 counting only the distinct ones).

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 131141252000 its reverse (252141131), we get a palindrome (131393393131).

The spelling of 131141252000 in words is "one hundred thirty-one billion, one hundred forty-one million, two hundred fifty-two thousand".