Base | Representation |
---|---|
bin | 11101110100010111111000… |
… | …111001010001001110011100 |
3 | 122012100002111012010121112220 |
4 | 131310113320321101032130 |
5 | 114142114130011223400 |
6 | 1142525554212225340 |
7 | 36423504141242313 |
oct | 3564277071211634 |
9 | 565302435117486 |
10 | 131142412211100 |
11 | 388712038aa154 |
12 | 1286034060b250 |
13 | 58238a40b5754 |
14 | 245548035127a |
15 | 10264ad6ba7a0 |
hex | 7745f8e5139c |
131142412211100 has 72 divisors (see below), whose sum is σ = 381951551952768. Its totient is φ = 34739711832000.
The previous prime is 131142412211089. The next prime is 131142412211101. The reversal of 131142412211100 is 1112214241131.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131142412211101) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1447442694 + ... + 1447533293.
Almost surely, 2131142412211100 is an apocalyptic number.
131142412211100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131142412211100 is an abundant number, since it is smaller than the sum of its proper divisors (250809139741668).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131142412211100 is a wasteful number, since it uses less digits than its factorization.
131142412211100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2894976155 (or 2894976148 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 24.
Adding to 131142412211100 its reverse (1112214241131), we get a palindrome (132254626452231).
The spelling of 131142412211100 in words is "one hundred thirty-one trillion, one hundred forty-two billion, four hundred twelve million, two hundred eleven thousand, one hundred".
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