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131153144424220 = 2252316313799126761
BaseRepresentation
bin11101110100100001111000…
…100101011010011100011100
3122012101010012010200112020201
4131310201320211122130130
5114142303114433033340
61142534531152553244
736424334116452352
oct3564417045323434
9565333163615221
10131153144424220
1138875810965776
1212862436852824
1358248c46b0709
142455bbb8357d2
1510268da9b079a
hex77487895a71c

131153144424220 has 96 divisors (see below), whose sum is σ = 289182860467200. Its totient is φ = 49868471093760.

The previous prime is 131153144424173. The next prime is 131153144424223. The reversal of 131153144424220 is 22424441351131.

It is a super-2 number, since 2×1311531444242202 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131153144424220.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131153144424223) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1034585640 + ... + 1034712400.

It is an arithmetic number, because the mean of its divisors is an integer number (3012321463200).

Almost surely, 2131153144424220 is an apocalyptic number.

131153144424220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131153144424220, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (144591430233600).

131153144424220 is an abundant number, since it is smaller than the sum of its proper divisors (158029716042980).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131153144424220 is a wasteful number, since it uses less digits than its factorization.

131153144424220 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 140755 (or 140753 counting only the distinct ones).

The product of its (nonzero) digits is 92160, while the sum is 37.

Adding to 131153144424220 its reverse (22424441351131), we get a palindrome (153577585775351).

The spelling of 131153144424220 in words is "one hundred thirty-one trillion, one hundred fifty-three billion, one hundred forty-four million, four hundred twenty-four thousand, two hundred twenty".

Divisors: 1 2 4 5 10 20 23 46 92 115 163 230 326 460 652 815 1630 3260 3749 7498 13799 14996 18745 27598 37490 55196 68995 74980 126761 137990 253522 275980 317377 507044 633805 634754 1267610 1269508 1586885 2249237 2535220 2915503 3173770 4498474 5831006 6347540 8996948 11246185 11662012 14577515 20662043 22492370 29155030 41324086 44984740 51732451 58310060 82648172 103310215 103464902 206620430 206929804 258662255 413240860 475226989 517324510 950453978 1034649020 1749175039 1900907956 2376134945 3498350078 4752269890 6996700156 8745875195 9504539780 17491750390 34983500780 40231025897 80462051794 160924103588 201155129485 285115531357 402310258970 570231062714 804620517940 1140462125428 1425577656785 2851155313570 5702310627140 6557657221211 13115314442422 26230628884844 32788286106055 65576572212110 131153144424220