Base | Representation |
---|---|
bin | 11101110101010000011010… |
… | …001011010001110001110110 |
3 | 122012112220010122010220222010 |
4 | 131311100122023101301312 |
5 | 114144112422112402410 |
6 | 1143013512212545050 |
7 | 36431053063051653 |
oct | 3565203213216166 |
9 | 565486118126863 |
10 | 131203100122230 |
11 | 38894a1661a004 |
12 | 12870058922186 |
13 | 582952620b736 |
14 | 245839a312c2a |
15 | 1027d61503c20 |
hex | 77541a2d1c76 |
131203100122230 has 32 divisors (see below), whose sum is σ = 328578198568704. Its totient is φ = 33466298002016.
The previous prime is 131203100122219. The next prime is 131203100122247. The reversal of 131203100122230 is 32221001302131.
It is a junction number, because it is equal to n+sod(n) for n = 131203100122197 and 131203100122206.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 95074709544 + ... + 95074710923.
It is an arithmetic number, because the mean of its divisors is an integer number (10268068705272).
Almost surely, 2131203100122230 is an apocalyptic number.
131203100122230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131203100122230 is an abundant number, since it is smaller than the sum of its proper divisors (197375098446474).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131203100122230 is a wasteful number, since it uses less digits than its factorization.
131203100122230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 190149420500.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 131203100122230 its reverse (32221001302131), we get a palindrome (163424101424361).
The spelling of 131203100122230 in words is "one hundred thirty-one trillion, two hundred three billion, one hundred million, one hundred twenty-two thousand, two hundred thirty".
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