131211421440440 has 128 divisors (see below), whose sum is σ = 322319675243520. Its totient is φ = 47675438745600.

The previous prime is 131211421440433. The next prime is 131211421440467. The reversal of 131211421440440 is 44044124112131.

It is a junction number, because it is equal to n+sod(n) for n = 131211421440397 and 131211421440406.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3692230352 + ... + 3692265888.

It is an arithmetic number, because the mean of its divisors is an integer number (2518122462840).

Almost surely, 2^{131211421440440} is an apocalyptic number.

131211421440440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131211421440440 is an abundant number, since it is smaller than the sum of its proper divisors (191108253803080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131211421440440 is a wasteful number, since it uses less digits than its factorization.

131211421440440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41973 (or 41969 counting only the distinct ones).

The product of its (nonzero) digits is 12288, while the sum is 32.

Adding to 131211421440440 its reverse (44044124112131), we get a palindrome (175255545552571).

The spelling of 131211421440440 in words is "one hundred thirty-one trillion, two hundred eleven billion, four hundred twenty-one million, four hundred forty thousand, four hundred forty".