13121402114040 has 256 divisors, whose sum is σ = 43297673126400. Its totient is φ = 3154705612800.

The previous prime is 13121402114021. The next prime is 13121402114057. The reversal of 13121402114040 is 4041120412131.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a self number, because there is not a number n which added to its sum of digits gives 13121402114040.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 174818920 + ... + 174893960.

It is an arithmetic number, because the mean of its divisors is an integer number (169131535650).

Almost surely, 2^{13121402114040} is an apocalyptic number.

13121402114040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13121402114040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21648836563200).

13121402114040 is an abundant number, since it is smaller than the sum of its proper divisors (30176271012360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13121402114040 is a wasteful number, since it uses less digits than its factorization.

13121402114040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 76158 (or 76154 counting only the distinct ones).

The product of its (nonzero) digits is 768, while the sum is 24.

Adding to 13121402114040 its reverse (4041120412131), we get a palindrome (17162522526171).

The spelling of 13121402114040 in words is "thirteen trillion, one hundred twenty-one billion, four hundred two million, one hundred fourteen thousand, forty".