13121404031423 has 4 divisors (see below), whose sum is σ = 13122479833080. Its totient is φ = 13120328229768.

The previous prime is 13121404031377. The next prime is 13121404031447. The reversal of 13121404031423 is 32413040412131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13121404031423 - 2¹² = 13121404027327 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13121404021423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 537882533 + ... + 537906926.

It is an arithmetic number, because the mean of its divisors is an integer number (3280619958270).

Almost surely, 2^{13121404031423} is an apocalyptic number.

13121404031423 is a deficient number, since it is larger than the sum of its proper divisors (1075801657).

13121404031423 is a wasteful number, since it uses less digits than its factorization.

13121404031423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1075801656.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13121404031423 its reverse (32413040412131), we get a palindrome (45534444443554).

The spelling of 13121404031423 in words is "thirteen trillion, one hundred twenty-one billion, four hundred four million, thirty-one thousand, four hundred twenty-three".