131214041112015 has 64 divisors (see below), whose sum is σ = 239891939020800. Its totient is φ = 68018742410112.

The previous prime is 131214041111987. The next prime is 131214041112043. The reversal of 131214041112015 is 510211140412131.

131214041112015 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 1 + 40 + 411 + 1 + 201 + 5 = 666.

It is an interprime number because it is at equal distance from previous prime (131214041111987) and next prime (131214041112043).

It is not a de Polignac number, because 131214041112015 - 2¹³ = 131214041103823 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a self number, because there is not a number n which added to its sum of digits gives 131214041112015.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 84929695 + ... + 86460864.

It is an arithmetic number, because the mean of its divisors is an integer number (3748311547200).

Almost surely, 2^{131214041112015} is an apocalyptic number.

131214041112015 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

131214041112015 is a deficient number, since it is larger than the sum of its proper divisors (108677897908785).

131214041112015 is a wasteful number, since it uses less digits than its factorization.

131214041112015 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 171390733 (or 171390727 counting only the distinct ones).

The product of its (nonzero) digits is 960, while the sum is 27.

Adding to 131214041112015 its reverse (510211140412131), we get a palindrome (641425181524146).

The spelling of 131214041112015 in words is "one hundred thirty-one trillion, two hundred fourteen billion, forty-one million, one hundred twelve thousand, fifteen".