Base | Representation |
---|---|
bin | 10011000110000110011… |
… | …110001111100001100010 |
3 | 11122110001221111122221022 |
4 | 103012012132033201202 |
5 | 132444412100201010 |
6 | 2442454232125442 |
7 | 163543030213043 |
oct | 23060636174142 |
9 | 4573057448838 |
10 | 1312221100130 |
11 | 466567668646 |
12 | 192398236882 |
13 | 96984cc3335 |
14 | 477246bc8ca |
15 | 24201cbbd55 |
hex | 1318678f862 |
1312221100130 has 32 divisors (see below), whose sum is σ = 2465500059648. Its totient is φ = 501902913600.
The previous prime is 1312221100121. The next prime is 1312221100133. The reversal of 1312221100130 is 310011222131.
It is a junction number, because it is equal to n+sod(n) for n = 1312221100099 and 1312221100108.
It is not an unprimeable number, because it can be changed into a prime (1312221100133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 227906 + ... + 1635965.
It is an arithmetic number, because the mean of its divisors is an integer number (77046876864).
Almost surely, 21312221100130 is an apocalyptic number.
1312221100130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1312221100130 is a deficient number, since it is larger than the sum of its proper divisors (1153278959518).
1312221100130 is a wasteful number, since it uses less digits than its factorization.
1312221100130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1866962.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1312221100130 its reverse (310011222131), we get a palindrome (1622232322261).
The spelling of 1312221100130 in words is "one trillion, three hundred twelve billion, two hundred twenty-one million, one hundred thousand, one hundred thirty".
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