Base | Representation |
---|---|
bin | 1011111011110101010010… |
… | …1010011110101100100000 |
3 | 1201110111120202111111200112 |
4 | 2332331110222132230200 |
5 | 3204444433122324300 |
6 | 43524225244110452 |
7 | 2523033624303266 |
oct | 276752452365440 |
9 | 51414522444615 |
10 | 13122545511200 |
11 | 41aa270923084 |
12 | 157b2a1b35428 |
13 | 7425b2348118 |
14 | 3351c5468436 |
15 | 17b532d57e35 |
hex | bef54a9eb20 |
13122545511200 has 72 divisors (see below), whose sum is σ = 32105514498372. Its totient is φ = 5237532241920.
The previous prime is 13122545511191. The next prime is 13122545511241. The reversal of 13122545511200 is 211554522131.
It can be written as a sum of positive squares in 6 ways, for example, as 4787291488144 + 8335254023056 = 2187988^2 + 2887084^2 .
It is a Harshad number since it is a multiple of its sum of digits (32).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 17580989 + ... + 18312188.
Almost surely, 213122545511200 is an apocalyptic number.
13122545511200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13122545511200 is an abundant number, since it is smaller than the sum of its proper divisors (18982968987172).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13122545511200 is a wasteful number, since it uses less digits than its factorization.
13122545511200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35893654 (or 35893641 counting only the distinct ones).
The product of its (nonzero) digits is 12000, while the sum is 32.
The spelling of 13122545511200 in words is "thirteen trillion, one hundred twenty-two billion, five hundred forty-five million, five hundred eleven thousand, two hundred".
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