Base | Representation |
---|---|
bin | 11101110101101100100100… |
… | …110110101001010101000000 |
3 | 122012122210012101101211112122 |
4 | 131311230210312221111000 |
5 | 114200111342033042422 |
6 | 1143035433240543412 |
7 | 36433203414055115 |
oct | 3565544466512500 |
9 | 565583171354478 |
10 | 131233344034112 |
11 | 388a6826508701 |
12 | 12875a99481b68 |
13 | 582c335c94098 |
14 | 2459a28cd090c |
15 | 1028a3175cd42 |
hex | 775b24da9540 |
131233344034112 has 28 divisors (see below), whose sum is σ = 261553355599380. Its totient is φ = 65330136324096.
The previous prime is 131233344034103. The next prime is 131233344034127. The reversal of 131233344034112 is 211430443332131.
It can be written as a sum of positive squares in 2 ways, for example, as 66169374415936 + 65063969618176 = 8134456^2 + 8066224^2 .
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4477105433 + ... + 4477134744.
Almost surely, 2131233344034112 is an apocalyptic number.
It is an amenable number.
131233344034112 is a deficient number, since it is larger than the sum of its proper divisors (130320011565268).
131233344034112 is an equidigital number, since it uses as much as digits as its factorization.
131233344034112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8954240418 (or 8954240408 counting only the distinct ones).
The product of its (nonzero) digits is 62208, while the sum is 35.
Adding to 131233344034112 its reverse (211430443332131), we get a palindrome (342663787366243).
The spelling of 131233344034112 in words is "one hundred thirty-one trillion, two hundred thirty-three billion, three hundred forty-four million, thirty-four thousand, one hundred twelve".
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