1312411413105 has 64 divisors (see below), whose sum is σ = 2516465952000. Its totient is φ = 645129225216.

The previous prime is 1312411413091. The next prime is 1312411413143. The reversal of 1312411413105 is 5013141142131.

1312411413105 is a `hidden beast` number, since 1 + 3 + 1 + 241 + 1 + 413 + 1 + 0 + 5 = 666.

It is not a de Polignac number, because 1312411413105 - 2⁵ = 1312411413073 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 589161 + ... + 1723929.

It is an arithmetic number, because the mean of its divisors is an integer number (39319780500).

Almost surely, 2^{1312411413105} is an apocalyptic number.

1312411413105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

1312411413105 is a deficient number, since it is larger than the sum of its proper divisors (1204054538895).

1312411413105 is a wasteful number, since it uses less digits than its factorization.

1312411413105 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1135455 (or 1135449 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 27.

Adding to 1312411413105 its reverse (5013141142131), we get a palindrome (6325552555236).

The spelling of 1312411413105 in words is "one trillion, three hundred twelve billion, four hundred eleven million, four hundred thirteen thousand, one hundred five".