131252422120400 has 120 divisors (see below), whose sum is σ = 367736378395200. Its totient is φ = 45000830394240.

The previous prime is 131252422120373. The next prime is 131252422120409. The reversal of 131252422120400 is 4021224252131.

It is a super-3 number, since 3×131252422120400³ (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131252422120409) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 478187954 + ... + 478462353.

It is an arithmetic number, because the mean of its divisors is an integer number (3064469819960).

Almost surely, 2^{131252422120400} is an apocalyptic number.

131252422120400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131252422120400 is an abundant number, since it is smaller than the sum of its proper divisors (236483956274800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131252422120400 is an equidigital number, since it uses as much as digits as its factorization.

131252422120400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 956650346 (or 956650321 counting only the distinct ones).

The product of its (nonzero) digits is 7680, while the sum is 29.

Adding to 131252422120400 its reverse (4021224252131), we get a palindrome (135273646372531).

The spelling of 131252422120400 in words is "one hundred thirty-one trillion, two hundred fifty-two billion, four hundred twenty-two million, one hundred twenty thousand, four hundred".