Base | Representation |
---|---|
bin | 1011111100010001111001… |
… | …0010101100100001101000 |
3 | 1201111020101211111121102100 |
4 | 2333010132102230201220 |
5 | 3210111144122210240 |
6 | 43531535152333400 |
7 | 2523425113032153 |
oct | 277043622544150 |
9 | 51436354447370 |
10 | 13130223241320 |
11 | 4202550796389 |
12 | 1580885244260 |
13 | 743236b93ab3 |
14 | 335713002c9a |
15 | 17b831de5e30 |
hex | bf11e4ac868 |
13130223241320 has 48 divisors (see below), whose sum is σ = 42673225535460. Its totient is φ = 3501392864256.
The previous prime is 13130223241301. The next prime is 13130223241433. The reversal of 13130223241320 is 2314232203131.
13130223241320 is a `hidden beast` number, since 1 + 3 + 1 + 3 + 0 + 223 + 2 + 413 + 20 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 11641593872484 + 1488629368836 = 3411978^2 + 1220094^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 18236420809 + ... + 18236421528.
Almost surely, 213130223241320 is an apocalyptic number.
13130223241320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13130223241320 is an abundant number, since it is smaller than the sum of its proper divisors (29543002294140).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13130223241320 is a wasteful number, since it uses less digits than its factorization.
13130223241320 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36472842354 (or 36472842347 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 13130223241320 its reverse (2314232203131), we get a palindrome (15444455444451).
The spelling of 13130223241320 in words is "thirteen trillion, one hundred thirty billion, two hundred twenty-three million, two hundred forty-one thousand, three hundred twenty".
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