Base | Representation |
---|---|
bin | 11000011101011101… |
… | …01100111001100101 |
3 | 1020220012020000022210 |
4 | 30032232230321211 |
5 | 203343244303240 |
6 | 10011024514033 |
7 | 643265242320 |
oct | 141656547145 |
9 | 36805200283 |
10 | 13132025445 |
11 | 56297600a0 |
12 | 2665a7b919 |
13 | 1313849376 |
14 | 8c80d57b7 |
15 | 51cd30780 |
hex | 30ebace65 |
13132025445 has 128 divisors (see below), whose sum is σ = 28262338560. Its totient is φ = 5039124480.
The previous prime is 13132025441. The next prime is 13132025447. The reversal of 13132025445 is 54452023131.
It is not a de Polignac number, because 13132025445 - 22 = 13132025441 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13132025441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 1034346 + ... + 1046964.
It is an arithmetic number, because the mean of its divisors is an integer number (220799520).
Almost surely, 213132025445 is an apocalyptic number.
13132025445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13132025445 is an abundant number, since it is smaller than the sum of its proper divisors (15130313115).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13132025445 is a wasteful number, since it uses less digits than its factorization.
13132025445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12715.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 13132025445 its reverse (54452023131), we get a palindrome (67584048576).
The spelling of 13132025445 in words is "thirteen billion, one hundred thirty-two million, twenty-five thousand, four hundred forty-five".
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