Base | Representation |
---|---|
bin | 1011111100011010001001… |
… | …1011011001001101111000 |
3 | 1201111110010022221102002101 |
4 | 2333012202123121031320 |
5 | 3210130214132122130 |
6 | 43532543143513144 |
7 | 2523534052114012 |
oct | 277064233311570 |
9 | 51443108842071 |
10 | 13132440114040 |
11 | 420348909a6a5 |
12 | 15811a37587b4 |
13 | 7434cb2522c0 |
14 | 3358835d31b2 |
15 | 17b9118471ca |
hex | bf1a26d9378 |
13132440114040 has 32 divisors (see below), whose sum is σ = 31820912585280. Its totient is φ = 4848900964992.
The previous prime is 13132440113963. The next prime is 13132440114071. The reversal of 13132440114040 is 4041104423131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12627345744 + ... + 12627346783.
It is an arithmetic number, because the mean of its divisors is an integer number (994403518290).
Almost surely, 213132440114040 is an apocalyptic number.
13132440114040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13132440114040 is an abundant number, since it is smaller than the sum of its proper divisors (18688472471240).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13132440114040 is a wasteful number, since it uses less digits than its factorization.
13132440114040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25254692551 (or 25254692547 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 13132440114040 its reverse (4041104423131), we get a palindrome (17173544537171).
The spelling of 13132440114040 in words is "thirteen trillion, one hundred thirty-two billion, four hundred forty million, one hundred fourteen thousand, forty".
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