131343203101240 has 256 divisors, whose sum is σ = 332799546481920. Its totient is φ = 46288670883840.

The previous prime is 131343203101151. The next prime is 131343203101267. The reversal of 131343203101240 is 42101302343131.

It is a junction number, because it is equal to n+sod(n) for n = 131343203101199 and 131343203101208.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 15945510402 + ... + 15945518638.

It is an arithmetic number, because the mean of its divisors is an integer number (1299998228445).

Almost surely, 2^{131343203101240} is an apocalyptic number.

131343203101240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131343203101240, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (166399773240960).

131343203101240 is an abundant number, since it is smaller than the sum of its proper divisors (201456343380680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131343203101240 is a wasteful number, since it uses less digits than its factorization.

131343203101240 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10962 (or 10958 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 131343203101240 its reverse (42101302343131), we get a palindrome (173444505444371).

The spelling of 131343203101240 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred three million, one hundred one thousand, two hundred forty".