Base | Representation |
---|---|
bin | 11101110111010010111001… |
… | …011000001000110010110000 |
3 | 122020001021210010122101202101 |
4 | 131313102321120020302300 |
5 | 114203411343231232422 |
6 | 1143202123202230144 |
7 | 36444143120423632 |
oct | 3567227130106260 |
9 | 566037703571671 |
10 | 131343210024112 |
11 | 38939384a48049 |
12 | 1289323b355354 |
13 | 58397c47a0218 |
14 | 246108c38ca52 |
15 | 102b811bd3c27 |
hex | 7774b9608cb0 |
131343210024112 has 20 divisors (see below), whose sum is σ = 263252554575120. Its totient is φ = 63407066907968.
The previous prime is 131343210024007. The next prime is 131343210024119. The reversal of 131343210024112 is 211420012343131.
It is not an unprimeable number, because it can be changed into a prime (131343210024119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141533631028 + ... + 141533631955.
It is an arithmetic number, because the mean of its divisors is an integer number (13162627728756).
Almost surely, 2131343210024112 is an apocalyptic number.
It is an amenable number.
131343210024112 is an abundant number, since it is smaller than the sum of its proper divisors (131909344551008).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131343210024112 is a wasteful number, since it uses less digits than its factorization.
131343210024112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 283067263020 (or 283067263014 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 131343210024112 its reverse (211420012343131), we get a palindrome (342763222367243).
The spelling of 131343210024112 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred ten million, twenty-four thousand, one hundred twelve".
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