Base | Representation |
---|---|
bin | 11000011101101111… |
… | …11000001101111100 |
3 | 1020220100202020021010 |
4 | 30032313320031330 |
5 | 203344403243400 |
6 | 10011152235220 |
7 | 643324552020 |
oct | 141667701574 |
9 | 36810666233 |
10 | 13134431100 |
11 | 563005353a |
12 | 266683bb10 |
13 | 13141ac32b |
14 | 8c8560380 |
15 | 51d158450 |
hex | 30edf837c |
13134431100 has 72 divisors (see below), whose sum is σ = 43431192448. Its totient is φ = 3002155200.
The previous prime is 13134431099. The next prime is 13134431111. The reversal of 13134431100 is 113443131.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3125146 + ... + 3129345.
Almost surely, 213134431100 is an apocalyptic number.
13134431100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13134431100 is an abundant number, since it is smaller than the sum of its proper divisors (30296761348).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13134431100 is a wasteful number, since it uses less digits than its factorization.
13134431100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6254515 (or 6254508 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13134431100 its reverse (113443131), we get a palindrome (13247874231).
The spelling of 13134431100 in words is "thirteen billion, one hundred thirty-four million, four hundred thirty-one thousand, one hundred".
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