Base | Representation |
---|---|
bin | 11101111000001001111011… |
… | …101011010101011100110000 |
3 | 122020020221022112011022110112 |
4 | 131320021323223111130300 |
5 | 114210343404412131230 |
6 | 1143245215120120452 |
7 | 36451334412425306 |
oct | 3570117353253460 |
9 | 566227275138415 |
10 | 131402304411440 |
11 | 3896144a209987 |
12 | 128a2791a66128 |
13 | 584225171a10a |
14 | 2463c96864276 |
15 | 102d11eb9bd95 |
hex | 77827bad5730 |
131402304411440 has 160 divisors (see below), whose sum is σ = 334099856972736. Its totient is φ = 47870848696320.
The previous prime is 131402304411439. The next prime is 131402304411529. The reversal of 131402304411440 is 44114403204131.
It is a junction number, because it is equal to n+sod(n) for n = 131402304411397 and 131402304411406.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7224506 + ... + 17748185.
Almost surely, 2131402304411440 is an apocalyptic number.
131402304411440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131402304411440 is an abundant number, since it is smaller than the sum of its proper divisors (202697552561296).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131402304411440 is a wasteful number, since it uses less digits than its factorization.
131402304411440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24972847 (or 24972841 counting only the distinct ones).
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 131402304411440 its reverse (44114403204131), we get a palindrome (175516707615571).
The spelling of 131402304411440 in words is "one hundred thirty-one trillion, four hundred two billion, three hundred four million, four hundred eleven thousand, four hundred forty".
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