131413100213440 has 112 divisors (see below), whose sum is σ = 313403516838144. Its totient is φ = 52485321420800.

The previous prime is 131413100213323. The next prime is 131413100213441. The reversal of 131413100213440 is 44312001314131.

It is a junction number, because it is equal to n+sod(n) for n = 131413100213399 and 131413100213408.

It is not an unprimeable number, because it can be changed into a prime (131413100213441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 664472970 + ... + 664670710.

Almost surely, 2^{131413100213440} is an apocalyptic number.

131413100213440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131413100213440 is an abundant number, since it is smaller than the sum of its proper divisors (181990416624704).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131413100213440 is a wasteful number, since it uses less digits than its factorization.

131413100213440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 200906 (or 200896 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 131413100213440 its reverse (44312001314131), we get a palindrome (175725101527571).

The spelling of 131413100213440 in words is "one hundred thirty-one trillion, four hundred thirteen billion, one hundred million, two hundred thirteen thousand, four hundred forty".