Base | Representation |
---|---|
bin | 1011111110100110111100… |
… | …1111010011010111000000 |
3 | 1201122001200101120221221210 |
4 | 2333221233033103113000 |
5 | 3211240120404340333 |
6 | 44002153425050120 |
7 | 2526342504002160 |
oct | 277515717232700 |
9 | 51561611527853 |
10 | 13170236011968 |
11 | 4218513977182 |
12 | 1588591486940 |
13 | 746c42798049 |
14 | 33762b1765a0 |
15 | 17c8c4aa1a63 |
hex | bfa6f3d35c0 |
13170236011968 has 56 divisors (see below), whose sum is σ = 39824285087872. Its totient is φ = 3762924574464.
The previous prime is 13170236011967. The next prime is 13170236011993. The reversal of 13170236011968 is 86911063207131.
It is a tau number, because it is divible by the number of its divisors (56).
It is a super-3 number, since 3×131702360119683 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (48).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13170236011967) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4899640030 + ... + 4899642717.
Almost surely, 213170236011968 is an apocalyptic number.
It is an amenable number.
13170236011968 is an abundant number, since it is smaller than the sum of its proper divisors (26654049075904).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13170236011968 is an equidigital number, since it uses as much as digits as its factorization.
13170236011968 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9799282769 (or 9799282759 counting only the distinct ones).
The product of its (nonzero) digits is 326592, while the sum is 48.
The spelling of 13170236011968 in words is "thirteen trillion, one hundred seventy billion, two hundred thirty-six million, eleven thousand, nine hundred sixty-eight".
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