Base | Representation |
---|---|
bin | 1100000000011110001011… |
… | …1001001100100100010000 |
3 | 1201202010021212220011220010 |
4 | 3000013202321030210100 |
5 | 3212301142213120404 |
6 | 44025005330114520 |
7 | 2531554562102214 |
oct | 300074271144420 |
9 | 51663255804803 |
10 | 13202241145104 |
11 | 4230047a43430 |
12 | 1592823a1ba40 |
13 | 749c733b3a4b |
14 | 338dc5a14944 |
15 | 17d649754189 |
hex | c01e2e4c910 |
13202241145104 has 40 divisors (see below), whose sum is σ = 37206315955872. Its totient is φ = 4000679134720.
The previous prime is 13202241145099. The next prime is 13202241145217. The reversal of 13202241145104 is 40154114220231.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12502121769 + ... + 12502122824.
Almost surely, 213202241145104 is an apocalyptic number.
It is an amenable number.
13202241145104 is an abundant number, since it is smaller than the sum of its proper divisors (24004074810768).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13202241145104 is a wasteful number, since it uses less digits than its factorization.
13202241145104 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25004244615 (or 25004244609 counting only the distinct ones).
The product of its (nonzero) digits is 7680, while the sum is 30.
Adding to 13202241145104 its reverse (40154114220231), we get a palindrome (53356355365335).
The spelling of 13202241145104 in words is "thirteen trillion, two hundred two billion, two hundred forty-one million, one hundred forty-five thousand, one hundred four".
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