Base | Representation |
---|---|
bin | 11110000001011100110111… |
… | …000100000101110011001100 |
3 | 122022112000011112011012200020 |
4 | 132001130313010011303030 |
5 | 114301330134432301030 |
6 | 1144454502343302140 |
7 | 36545440430304414 |
oct | 3601346704056314 |
9 | 568460145135606 |
10 | 132041103400140 |
11 | 390883546239a0 |
12 | 1298654a44a950 |
13 | 588a5656702ac |
14 | 2486b759a1644 |
15 | 103ea5ad66510 |
hex | 781737105ccc |
132041103400140 has 96 divisors (see below), whose sum is σ = 427050584722944. Its totient is φ = 30127025372160.
The previous prime is 132041103400103. The next prime is 132041103400181. The reversal of 132041103400140 is 41004301140231.
It is a self number, because there is not a number n which added to its sum of digits gives 132041103400140.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5884173424 + ... + 5884195863.
It is an arithmetic number, because the mean of its divisors is an integer number (4448443590864).
Almost surely, 2132041103400140 is an apocalyptic number.
132041103400140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132041103400140 is an abundant number, since it is smaller than the sum of its proper divisors (295009481322804).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132041103400140 is a wasteful number, since it uses less digits than its factorization.
132041103400140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11768369327 (or 11768369325 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 132041103400140 its reverse (41004301140231), we get a palindrome (173045404540371).
The spelling of 132041103400140 in words is "one hundred thirty-two trillion, forty-one billion, one hundred three million, four hundred thousand, one hundred forty".
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