Base | Representation |
---|---|
bin | 111101100000111001… |
… | …0000000010011010000 |
3 | 110121222021200220101102 |
4 | 1323001302000103100 |
5 | 4131020113130000 |
6 | 140404100123532 |
7 | 12354364402226 |
oct | 1730162002320 |
9 | 417867626342 |
10 | 132100130000 |
11 | 51029096963 |
12 | 217280965a8 |
13 | c5c30098c7 |
14 | 657238ab16 |
15 | 36824043d5 |
hex | 1ec1c804d0 |
132100130000 has 50 divisors (see below), whose sum is σ = 319827648954. Its totient is φ = 52840048000.
The previous prime is 132100129963. The next prime is 132100130003. The reversal of 132100130000 is 31001231.
It can be written as a sum of positive squares in 5 ways, for example, as 61754238016 + 70345891984 = 248504^2 + 265228^2 .
It is a tau number, because it is divible by the number of its divisors (50).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132100130003) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 6595007 + ... + 6615006.
Almost surely, 2132100130000 is an apocalyptic number.
132100130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132100130000 is an abundant number, since it is smaller than the sum of its proper divisors (187727518954).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132100130000 is an equidigital number, since it uses as much as digits as its factorization.
132100130000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13210041 (or 13210020 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 11.
Adding to 132100130000 its reverse (31001231), we get a palindrome (132131131231).
The spelling of 132100130000 in words is "one hundred thirty-two billion, one hundred million, one hundred thirty thousand".
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