Base | Representation |
---|---|
bin | 11110000101001111000110… |
… | …001101110000010101011110 |
3 | 122100102212112022122122200020 |
4 | 132011033012031300111132 |
5 | 114320110330444111220 |
6 | 1145214200023013010 |
7 | 36603306101345160 |
oct | 3605170615602536 |
9 | 570385468578606 |
10 | 132301203113310 |
11 | 39178697088130 |
12 | 12a08a3929a166 |
13 | 58a8c46c8c70a |
14 | 24955ab890930 |
15 | 10466d0688040 |
hex | 7853c637055e |
132301203113310 has 128 divisors (see below), whose sum is σ = 416708095795200. Its totient is φ = 26044255969920.
The previous prime is 132301203113281. The next prime is 132301203113323. The reversal of 132301203113310 is 13311302103231.
It is a super-2 number, since 2×1323012031133102 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1507146850 + ... + 1507234629.
It is an arithmetic number, because the mean of its divisors is an integer number (3255531998400).
Almost surely, 2132301203113310 is an apocalyptic number.
132301203113310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132301203113310 is an abundant number, since it is smaller than the sum of its proper divisors (284406892681890).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132301203113310 is a wasteful number, since it uses less digits than its factorization.
132301203113310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3014381526.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 132301203113310 its reverse (13311302103231), we get a palindrome (145612505216541).
The spelling of 132301203113310 in words is "one hundred thirty-two trillion, three hundred one billion, two hundred three million, one hundred thirteen thousand, three hundred ten".
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