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132303100045440 = 273568907864607
BaseRepresentation
bin11110000101010000110111…
…010001111110100010000000
3122100110001102112001210100210
4132011100313101332202000
5114320123222102423230
61145215112144514120
736603404104116432
oct3605206721764200
9570401375053323
10132303100045440
113917947a928335
1212a0928861b940
1358a9189c8aa6c
14249570b79a652
151046791e8beb0
hex78543747e880

132303100045440 has 64 divisors (see below), whose sum is σ = 421716131400960. Its totient is φ = 35280826678272.

The previous prime is 132303100045429. The next prime is 132303100045553. The reversal of 132303100045440 is 44540001303231.

It is a tau number, because it is divible by the number of its divisors (64).

It is a super-2 number, since 2×1323031000454402 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 132303100045398 and 132303100045407.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34453930384 + ... + 34453934223.

It is an arithmetic number, because the mean of its divisors is an integer number (6589314553140).

Almost surely, 2132303100045440 is an apocalyptic number.

132303100045440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132303100045440 is an abundant number, since it is smaller than the sum of its proper divisors (289413031355520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132303100045440 is an equidigital number, since it uses as much as digits as its factorization.

132303100045440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68907864629 (or 68907864617 counting only the distinct ones).

The product of its (nonzero) digits is 17280, while the sum is 30.

Adding to 132303100045440 its reverse (44540001303231), we get a palindrome (176843101348671).

The spelling of 132303100045440 in words is "one hundred thirty-two trillion, three hundred three billion, one hundred million, forty-five thousand, four hundred forty".

Divisors: 1 2 3 4 5 6 8 10 12 15 16 20 24 30 32 40 48 60 64 80 96 120 128 160 192 240 320 384 480 640 960 1920 68907864607 137815729214 206723593821 275631458428 344539323035 413447187642 551262916856 689078646070 826894375284 1033617969105 1102525833712 1378157292140 1653788750568 2067235938210 2205051667424 2756314584280 3307577501136 4134471876420 4410103334848 5512629168560 6615155002272 8268943752840 8820206669696 11025258337120 13230310004544 16537887505680 22050516674240 26460620009088 33075775011360 44101033348480 66151550022720 132303100045440