Base | Representation |
---|---|
bin | 1100000010111010100010… |
… | …0100110110000010110000 |
3 | 1201220010121221020001210011 |
4 | 3000232220210312002300 |
5 | 3213443121333420100 |
6 | 44100150203544304 |
7 | 2534601633652525 |
oct | 300565044660260 |
9 | 51803557201704 |
10 | 13244212404400 |
11 | 424692569878a |
12 | 159a997b2b094 |
13 | 750c01989913 |
14 | 33b047d1914c |
15 | 17e7a4322bba |
hex | c0ba89360b0 |
13244212404400 has 60 divisors (see below), whose sum is σ = 31825830541032. Its totient is φ = 5296584401920.
The previous prime is 13244212404389. The next prime is 13244212404403. The reversal of 13244212404400 is 440421244231.
It is a happy number.
It is not an unprimeable number, because it can be changed into a prime (13244212404403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1510042 + ... + 5363641.
Almost surely, 213244212404400 is an apocalyptic number.
13244212404400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13244212404400 is an abundant number, since it is smaller than the sum of its proper divisors (18581618136632).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13244212404400 is a wasteful number, since it uses less digits than its factorization.
13244212404400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6878518 (or 6878507 counting only the distinct ones).
The product of its (nonzero) digits is 24576, while the sum is 31.
Adding to 13244212404400 its reverse (440421244231), we get a palindrome (13684633648631).
The spelling of 13244212404400 in words is "thirteen trillion, two hundred forty-four billion, two hundred twelve million, four hundred four thousand, four hundred".
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