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132520034113 = 383346005311
BaseRepresentation
bin111101101101011001…
…1110011111101000001
3110200001112211020112121
41323122303303331001
54132400112042423
6140513500124241
712400653463405
oct1733263637501
9420045736477
10132520034113
1151224117055
1221824836681
13c65bcc9a8c
1465b2053105
1536a91ea45d
hex1edacf3f41

132520034113 has 4 divisors (see below), whose sum is σ = 132866039808. Its totient is φ = 132174028420.

The previous prime is 132520034047. The next prime is 132520034131. The reversal of 132520034113 is 311430025231.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132520034113 - 213 = 132520025921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132590034113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 173002273 + ... + 173003038.

It is an arithmetic number, because the mean of its divisors is an integer number (33216509952).

Almost surely, 2132520034113 is an apocalyptic number.

It is an amenable number.

132520034113 is a deficient number, since it is larger than the sum of its proper divisors (346005695).

132520034113 is an equidigital number, since it uses as much as digits as its factorization.

132520034113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 346005694.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 132520034113 its reverse (311430025231), we get a palindrome (443950059344).

The spelling of 132520034113 in words is "one hundred thirty-two billion, five hundred twenty million, thirty-four thousand, one hundred thirteen".

Divisors: 1 383 346005311 132520034113