13300111214320 has 40 divisors (see below), whose sum is σ = 35340295513824. Its totient is φ = 4560038130432.

The previous prime is 13300111214311. The next prime is 13300111214363. The reversal of 13300111214320 is 2341211100331.

It is a tau number, because it is divible by the number of its divisors (40).

It is a junction number, because it is equal to n+sod(n) for n = 13300111214291 and 13300111214300.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11875098739 + ... + 11875099858.

Almost surely, 2^{13300111214320} is an apocalyptic number.

13300111214320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13300111214320 is an abundant number, since it is smaller than the sum of its proper divisors (22040184299504).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13300111214320 is a wasteful number, since it uses less digits than its factorization.

13300111214320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23750198617 (or 23750198611 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 13300111214320 its reverse (2341211100331), we get a palindrome (15641322314651).

The spelling of 13300111214320 in words is "thirteen trillion, three hundred billion, one hundred eleven million, two hundred fourteen thousand, three hundred twenty".