Base | Representation |
---|---|
bin | 11110001111011101101010… |
… | …101100101001001110100010 |
3 | 122102221001200101122212210120 |
4 | 132033131222230221032202 |
5 | 114413114234314441310 |
6 | 1150513114042541110 |
7 | 40005140105260224 |
oct | 3617355254511642 |
9 | 572831611585716 |
10 | 133004042343330 |
11 | 39419774549314 |
12 | 12b010a8807796 |
13 | 592a2c5710b02 |
14 | 24bb603cac414 |
15 | 1059b18b28b70 |
hex | 78f76ab293a2 |
133004042343330 has 128 divisors (see below), whose sum is σ = 333267801255936. Its totient is φ = 33907401158400.
The previous prime is 133004042343299. The next prime is 133004042343371. The reversal of 133004042343330 is 33343240400331.
It is a junction number, because it is equal to n+sod(n) for n = 133004042343291 and 133004042343300.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 16147141972 + ... + 16147150208.
It is an arithmetic number, because the mean of its divisors is an integer number (2603654697312).
Almost surely, 2133004042343330 is an apocalyptic number.
133004042343330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133004042343330 is an abundant number, since it is smaller than the sum of its proper divisors (200263758912606).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133004042343330 is a wasteful number, since it uses less digits than its factorization.
133004042343330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18032.
The product of its (nonzero) digits is 93312, while the sum is 33.
Adding to 133004042343330 its reverse (33343240400331), we get a palindrome (166347282743661).
The spelling of 133004042343330 in words is "one hundred thirty-three trillion, four billion, forty-two million, three hundred forty-three thousand, three hundred thirty".
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