Base | Representation |
---|---|
bin | 10011010110110001010… |
… | …101111001101011111000 |
3 | 11201011021100211022010020 |
4 | 103112301111321223320 |
5 | 133243041232444000 |
6 | 2455014312050440 |
7 | 165045422115321 |
oct | 23266125715370 |
9 | 4634240738106 |
10 | 1330120203000 |
11 | 4731121a6546 |
12 | 195952693a20 |
13 | 98578357974 |
14 | 48541963448 |
15 | 248ed394ba0 |
hex | 135b1579af8 |
1330120203000 has 64 divisors (see below), whose sum is σ = 4149975042720. Its totient is φ = 354698720000.
The previous prime is 1330120202993. The next prime is 1330120203007. The reversal of 1330120203000 is 3020210331.
It is an interprime number because it is at equal distance from previous prime (1330120202993) and next prime (1330120203007).
It is a super-2 number, since 2×13301202030002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1330120203007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 221683701 + ... + 221689700.
Almost surely, 21330120203000 is an apocalyptic number.
1330120203000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1330120203000 is an abundant number, since it is smaller than the sum of its proper divisors (2819854839720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1330120203000 is a wasteful number, since it uses less digits than its factorization.
1330120203000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 443373425 (or 443373411 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 15.
Adding to 1330120203000 its reverse (3020210331), we get a palindrome (1333140413331).
The spelling of 1330120203000 in words is "one trillion, three hundred thirty billion, one hundred twenty million, two hundred three thousand".
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