Base | Representation |
---|---|
bin | 1100000110001111010100… |
… | …0011101000110111000010 |
3 | 1202002121001120021122211010 |
4 | 3001203311003220313002 |
5 | 3220412111002321010 |
6 | 44142314030501350 |
7 | 2541663234353223 |
oct | 301436503506702 |
9 | 52077046248733 |
10 | 13301330120130 |
11 | 42690760a6a28 |
12 | 15a9a78664856 |
13 | 756405239850 |
14 | 33db05a8924a |
15 | 180ee89d5620 |
hex | c18f50e8dc2 |
13301330120130 has 32 divisors (see below), whose sum is σ = 34378822465344. Its totient is φ = 3274173567936.
The previous prime is 13301330120083. The next prime is 13301330120189. The reversal of 13301330120130 is 3102103310331.
It is a super-3 number, since 3×133013301201303 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13301330120097 and 13301330120106.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17052986944 + ... + 17052987723.
It is an arithmetic number, because the mean of its divisors is an integer number (1074338202042).
Almost surely, 213301330120130 is an apocalyptic number.
13301330120130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13301330120130 is an abundant number, since it is smaller than the sum of its proper divisors (21077492345214).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13301330120130 is a wasteful number, since it uses less digits than its factorization.
13301330120130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34105974690.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 13301330120130 its reverse (3102103310331), we get a palindrome (16403433430461).
The spelling of 13301330120130 in words is "thirteen trillion, three hundred one billion, three hundred thirty million, one hundred twenty thousand, one hundred thirty".
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