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13305344000 = 21253131999
BaseRepresentation
bin11000110010000111…
…10111000000000000
31021100021100111200112
430121003313000000
5204222132002000
610040135410452
7650501362244
oct143103670000
937307314615
1013305344000
115708579973
1226b3b23a28
131340721020
14903130424
1552d169235
hex3190f7000

13305344000 has 208 divisors, whose sum is σ = 35778288000. Its totient is φ = 4910284800.

The previous prime is 13305343993. The next prime is 13305344131. The reversal of 13305344000 is 44350331.

It is a tau number, because it is divible by the number of its divisors (208).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6655001 + ... + 6656999.

It is an arithmetic number, because the mean of its divisors is an integer number (172011000).

Almost surely, 213305344000 is an apocalyptic number.

13305344000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13305344000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17889144000).

13305344000 is an abundant number, since it is smaller than the sum of its proper divisors (22472944000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13305344000 is an equidigital number, since it uses as much as digits as its factorization.

13305344000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2051 (or 2019 counting only the distinct ones).

The product of its (nonzero) digits is 2160, while the sum is 23.

Adding to 13305344000 its reverse (44350331), we get a palindrome (13349694331).

The spelling of 13305344000 in words is "thirteen billion, three hundred five million, three hundred forty-four thousand".