133114551100 has 72 divisors (see below), whose sum is σ = 290617649280. Its totient is φ = 52922081280.

The previous prime is 133114551061. The next prime is 133114551103. The reversal of 133114551100 is 1155411331.

It is a super-2 number, since 2×133114551100² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133114551103) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 27770304 + ... + 27775096.

It is an arithmetic number, because the mean of its divisors is an integer number (4036356240).

Almost surely, 2^133114551100 is an apocalyptic number.

133114551100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133114551100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (145308824640).

133114551100 is an abundant number, since it is smaller than the sum of its proper divisors (157503098180).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133114551100 is a wasteful number, since it uses less digits than its factorization.

133114551100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6439 (or 6432 counting only the distinct ones).

The product of its (nonzero) digits is 900, while the sum is 25.

Adding to 133114551100 its reverse (1155411331), we get a palindrome (134269962431).

The spelling of 133114551100 in words is "one hundred thirty-three billion, one hundred fourteen million, five hundred fifty-one thousand, one hundred".