13312441404340 has 24 divisors (see below), whose sum is σ = 30106598253480. Its totient is φ = 4915362979968.

The previous prime is 13312441404331. The next prime is 13312441404403. The reversal of 13312441404340 is 4340414421331.

It can be written as a sum of positive squares in 4 ways, for example, as 1698236410896 + 11614204993444 = 1303164^2 + 3407962^2 .

It is a super-2 number, since 2×13312441404340² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13312441404296 and 13312441404305.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25600848595 + ... + 25600849114.

It is an arithmetic number, because the mean of its divisors is an integer number (1254441593895).

Almost surely, 2^{13312441404340} is an apocalyptic number.

13312441404340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13312441404340 is an abundant number, since it is smaller than the sum of its proper divisors (16794156849140).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13312441404340 is a wasteful number, since it uses less digits than its factorization.

13312441404340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51201697731 (or 51201697729 counting only the distinct ones).

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 13312441404340 its reverse (4340414421331), we get a palindrome (17652855825671).

The spelling of 13312441404340 in words is "thirteen trillion, three hundred twelve billion, four hundred forty-one million, four hundred four thousand, three hundred forty".