Base | Representation |
---|---|
bin | 11110010011111110101010… |
… | …000001100101000101010100 |
3 | 122111000201121202001002200200 |
4 | 132103332222001211011110 |
5 | 114433210233131110200 |
6 | 1151311432522540500 |
7 | 40036433453502666 |
oct | 3623765201450524 |
9 | 574021552032620 |
10 | 133314342441300 |
11 | 395293278a0679 |
12 | 12b51267667730 |
13 | 5950647460437 |
14 | 24cc63cd70536 |
15 | 1062c2a6c3800 |
hex | 793faa065154 |
133314342441300 has 54 divisors (see below), whose sum is σ = 417866400032718. Its totient is φ = 35550491317440.
The previous prime is 133314342441299. The next prime is 133314342441341. The reversal of 133314342441300 is 3144243413331.
133314342441300 is a `hidden beast` number, since 1 + 3 + 3 + 3 + 1 + 4 + 342 + 4 + 4 + 1 + 300 = 666.
It can be written as a sum of positive squares in 3 ways, for example, as 153728294724 + 133160614146576 = 392082^2 + 11539524^2 .
It is a Harshad number since it is a multiple of its sum of digits (36).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 74063522679 + ... + 74063524478.
Almost surely, 2133314342441300 is an apocalyptic number.
133314342441300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133314342441300 is an abundant number, since it is smaller than the sum of its proper divisors (284552057591418).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133314342441300 is a wasteful number, since it uses less digits than its factorization.
133314342441300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 148127047177 (or 148127047167 counting only the distinct ones).
The product of its (nonzero) digits is 124416, while the sum is 36.
Adding to 133314342441300 its reverse (3144243413331), we get a palindrome (136458585854631).
The spelling of 133314342441300 in words is "one hundred thirty-three trillion, three hundred fourteen billion, three hundred forty-two million, four hundred forty-one thousand, three hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •