Base | Representation |
---|---|
bin | 11110010100000100111001… |
… | …010010101101111010110000 |
3 | 122111001100220120122022220101 |
4 | 132110010321102231322300 |
5 | 114433312443001334440 |
6 | 1151314501333122144 |
7 | 40040061452620240 |
oct | 3624047122557260 |
9 | 574040816568811 |
10 | 133321041043120 |
11 | 39531154aa6337 |
12 | 12b52616a89354 |
13 | 5951174199058 |
14 | 24ccab6871b20 |
15 | 1062ebd80469a |
hex | 7941394adeb0 |
133321041043120 has 80 divisors (see below), whose sum is σ = 354259441301760. Its totient is φ = 45709246778112.
The previous prime is 133321041043117. The next prime is 133321041043123. The reversal of 133321041043120 is 21340140123331.
It is an interprime number because it is at equal distance from previous prime (133321041043117) and next prime (133321041043123).
It is a tau number, because it is divible by the number of its divisors (80).
It is a Harshad number since it is a multiple of its sum of digits (28).
It is not an unprimeable number, because it can be changed into a prime (133321041043123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29341359 + ... + 33579121.
It is an arithmetic number, because the mean of its divisors is an integer number (4428243016272).
Almost surely, 2133321041043120 is an apocalyptic number.
133321041043120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133321041043120 is an abundant number, since it is smaller than the sum of its proper divisors (220938400258640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133321041043120 is a wasteful number, since it uses less digits than its factorization.
133321041043120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4293962 (or 4293956 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 133321041043120 its reverse (21340140123331), we get a palindrome (154661181166451).
The spelling of 133321041043120 in words is "one hundred thirty-three trillion, three hundred twenty-one billion, forty-one million, forty-three thousand, one hundred twenty".
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