1340000000 has 144 divisors (see below), whose sum is σ = 3393350688. Its totient is φ = 528000000.

The previous prime is 1339999967. The next prime is 1340000003. The reversal of 1340000000 is 431.

It is a Harshad number since it is a multiple of its sum of digits (8).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340000003) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19999967 + ... + 20000033.

Almost surely, 2^1340000000 is an apocalyptic number.

1340000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1340000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1696675344).

1340000000 is an abundant number, since it is smaller than the sum of its proper divisors (2053350688).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1340000000 is an frugal number, since it uses more digits than its factorization.

1340000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 118 (or 74 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 8.

The square root of 1340000000 is about 36606.0104354463. The cubic root of 1340000000 is about 1102.4737714497.

Adding to 1340000000 its reverse (431), we get a palindrome (1340000431).

The spelling of 1340000000 in words is "one billion, three hundred forty million", and thus it is an aban number.