Base | Representation |
---|---|
bin | 11000111101101010… |
… | …00100101111001000 |
3 | 1021121000110211001001 |
4 | 30132311010233020 |
5 | 204421421201100 |
6 | 10053514104344 |
7 | 653055144250 |
oct | 143665045710 |
9 | 37530424031 |
10 | 13402131400 |
11 | 5758176759 |
12 | 272041b0b4 |
13 | 13577ab488 |
14 | 911d26960 |
15 | 5368d6d6a |
hex | 31ed44bc8 |
13402131400 has 48 divisors (see below), whose sum is σ = 35611381440. Its totient is φ = 4595016000.
The previous prime is 13402131383. The next prime is 13402131401. The reversal of 13402131400 is 413120431.
13402131400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (13402131401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4785076 + ... + 4787875.
It is an arithmetic number, because the mean of its divisors is an integer number (741903780).
Almost surely, 213402131400 is an apocalyptic number.
13402131400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13402131400 is an abundant number, since it is smaller than the sum of its proper divisors (22209250040).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13402131400 is a wasteful number, since it uses less digits than its factorization.
13402131400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9572974 (or 9572965 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 13402131400 its reverse (413120431), we get a palindrome (13815251831).
The spelling of 13402131400 in words is "thirteen billion, four hundred two million, one hundred thirty-one thousand, four hundred".
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