Base | Representation |
---|---|
bin | 111110011010100011… |
… | …0111111111110000000 |
3 | 110210222010112011120102 |
4 | 1330311012333332000 |
5 | 4144000430413004 |
6 | 141324055301532 |
7 | 12453340550060 |
oct | 1746506777600 |
9 | 423863464512 |
10 | 134035013504 |
11 | 519312a8537 |
12 | 21b8807a8a8 |
13 | c840b351a2 |
14 | 66b73353a0 |
15 | 374720311e |
hex | 1f351bff80 |
134035013504 has 64 divisors (see below), whose sum is σ = 305930844000. Its totient is φ = 57300172800.
The previous prime is 134035013479. The next prime is 134035013573. The reversal of 134035013504 is 405310530431.
It is a tau number, because it is divible by the number of its divisors (64).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 172772 + ... + 545820.
Almost surely, 2134035013504 is an apocalyptic number.
134035013504 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 134035013504, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (152965422000).
134035013504 is an abundant number, since it is smaller than the sum of its proper divisors (171895830496).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134035013504 is an equidigital number, since it uses as much as digits as its factorization.
134035013504 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 373471 (or 373459 counting only the distinct ones).
The product of its (nonzero) digits is 10800, while the sum is 29.
Adding to 134035013504 its reverse (405310530431), we get a palindrome (539345543935).
The spelling of 134035013504 in words is "one hundred thirty-four billion, thirty-five million, thirteen thousand, five hundred four".
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