Base | Representation |
---|---|
bin | 111110011100100001… |
… | …0111011011100000000 |
3 | 110211010201210102210100 |
4 | 1330321002323130000 |
5 | 4144114332231412 |
6 | 141334415002400 |
7 | 12455102106414 |
oct | 1747102733400 |
9 | 424121712710 |
10 | 134101055232 |
11 | 51965605681 |
12 | 21ba6209400 |
13 | c851719131 |
14 | 66c2006d44 |
15 | 374cdeaedc |
hex | 1f390bb700 |
134101055232 has 54 divisors (see below), whose sum is σ = 386646408512. Its totient is φ = 44700350976.
The previous prime is 134101055183. The next prime is 134101055233. The reversal of 134101055232 is 232550101431.
134101055232 is a `hidden beast` number, since 1 + 3 + 4 + 101 + 0 + 552 + 3 + 2 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 134101055196 and 134101055205.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134101055233) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 29099488 + ... + 29104095.
Almost surely, 2134101055232 is an apocalyptic number.
134101055232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
134101055232 is an abundant number, since it is smaller than the sum of its proper divisors (252545353280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134101055232 is an equidigital number, since it uses as much as digits as its factorization.
134101055232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58203605 (or 58203588 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 27.
Adding to 134101055232 its reverse (232550101431), we get a palindrome (366651156663).
The spelling of 134101055232 in words is "one hundred thirty-four billion, one hundred one million, fifty-five thousand, two hundred thirty-two".
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