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1341143105151 = 31372132581277
BaseRepresentation
bin10011100001000010010…
…110111011111001111111
311202012201120100202012110
4103201002112323321333
5133433130113331101
62504040155105103
7165615530205303
oct23410226737177
94665646322173
101341143105151
11477859357033
12197b0a142193
1399613c40685
1448ca98b5d03
1524d45e59cd6
hex138425bbe7f

1341143105151 has 8 divisors (see below), whose sum is σ = 1788321186864. Its totient is φ = 894030213440.

The previous prime is 1341143105149. The next prime is 1341143105171. The reversal of 1341143105151 is 1515013411431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1341143105151 - 21 = 1341143105149 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1341143105131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16249476 + ... + 16331801.

It is an arithmetic number, because the mean of its divisors is an integer number (223540148358).

Almost surely, 21341143105151 is an apocalyptic number.

1341143105151 is a deficient number, since it is larger than the sum of its proper divisors (447178081713).

1341143105151 is a wasteful number, since it uses less digits than its factorization.

1341143105151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32595001.

The product of its (nonzero) digits is 3600, while the sum is 30.

Adding to 1341143105151 its reverse (1515013411431), we get a palindrome (2856156516582).

The spelling of 1341143105151 in words is "one trillion, three hundred forty-one billion, one hundred forty-three million, one hundred five thousand, one hundred fifty-one".

Divisors: 1 3 13721 41163 32581277 97743831 447047701717 1341143105151