Base | Representation |
---|---|
bin | 1100001101110110101010… |
… | …1110101101011110110000 |
3 | 1202120002201212022001021110 |
4 | 3003131222232231132300 |
5 | 3230033022230130100 |
6 | 44322351314553320 |
7 | 2554304165524521 |
oct | 303355256553660 |
9 | 52502655261243 |
10 | 13432153364400 |
11 | 43095a9442721 |
12 | 160b2a8b98840 |
13 | 765853842264 |
14 | 346196610848 |
15 | 184603c63250 |
hex | c376abad7b0 |
13432153364400 has 120 divisors (see below), whose sum is σ = 43028479842304. Its totient is φ = 3581839699200.
The previous prime is 13432153364393. The next prime is 13432153364411. The reversal of 13432153364400 is 446335123431.
It is a tau number, because it is divible by the number of its divisors (120).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 118636617 + ... + 118749783.
Almost surely, 213432153364400 is an apocalyptic number.
13432153364400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13432153364400 is an abundant number, since it is smaller than the sum of its proper divisors (29596326477904).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13432153364400 is a wasteful number, since it uses less digits than its factorization.
13432153364400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 212099 (or 212088 counting only the distinct ones).
The product of its (nonzero) digits is 311040, while the sum is 39.
Adding to 13432153364400 its reverse (446335123431), we get a palindrome (13878488487831).
The spelling of 13432153364400 in words is "thirteen trillion, four hundred thirty-two billion, one hundred fifty-three million, three hundred sixty-four thousand, four hundred".
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