Base | Representation |
---|---|
bin | 1100001101111101111110… |
… | …0110110010011111000111 |
3 | 1202120021210111222221020212 |
4 | 3003133133212302133013 |
5 | 3230101031220101043 |
6 | 44323314042550035 |
7 | 2554403605532555 |
oct | 303373746623707 |
9 | 52507714887225 |
10 | 13434114222023 |
11 | 430a415285010 |
12 | 160b75580831b |
13 | 765aa6b63241 |
14 | 346300bdabd5 |
15 | 1846bae93018 |
hex | c37df9b27c7 |
13434114222023 has 8 divisors (see below), whose sum is σ = 14665497555456. Its totient is φ = 12204414259000.
The previous prime is 13434114222017. The next prime is 13434114222043. The reversal of 13434114222023 is 32022241143431.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13434114222023 - 218 = 13434113959879 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13434114222043) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 420825911 + ... + 420857832.
It is an arithmetic number, because the mean of its divisors is an integer number (1833187194432).
Almost surely, 213434114222023 is an apocalyptic number.
13434114222023 is a deficient number, since it is larger than the sum of its proper divisors (1231383333433).
13434114222023 is a wasteful number, since it uses less digits than its factorization.
13434114222023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 841685205.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 13434114222023 its reverse (32022241143431), we get a palindrome (45456355365454).
The spelling of 13434114222023 in words is "thirteen trillion, four hundred thirty-four billion, one hundred fourteen million, two hundred twenty-two thousand, twenty-three".
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