Base | Representation |
---|---|
bin | 10011100011101100111… |
… | …000110100000000010000 |
3 | 11202111002221211222022220 |
4 | 103203230320310000100 |
5 | 134010010023044100 |
6 | 2505232120301040 |
7 | 166046450314305 |
oct | 23435470640020 |
9 | 4674087758286 |
10 | 1344004112400 |
11 | 478a97313134 |
12 | 198588311780 |
13 | 9997b8ab181 |
14 | 4909b85b0ac |
15 | 24e621e5aa0 |
hex | 138ece34010 |
1344004112400 has 60 divisors (see below), whose sum is σ = 4305293177232. Its totient is φ = 358401096320.
The previous prime is 1344004112383. The next prime is 1344004112411. The reversal of 1344004112400 is 42114004431.
It is a tau number, because it is divible by the number of its divisors (60).
It is a super-2 number, since 2×13440041124002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 560000514 + ... + 560002913.
Almost surely, 21344004112400 is an apocalyptic number.
1344004112400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1344004112400 is an abundant number, since it is smaller than the sum of its proper divisors (2961289064832).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1344004112400 is a wasteful number, since it uses less digits than its factorization.
1344004112400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1120003448 (or 1120003437 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 1344004112400 its reverse (42114004431), we get a palindrome (1386118116831).
The spelling of 1344004112400 in words is "one trillion, three hundred forty-four billion, four million, one hundred twelve thousand, four hundred".
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