13440121103711 has 2 divisors, whose sum is σ = 13440121103712. Its totient is φ = 13440121103710.

The previous prime is 13440121103707. The next prime is 13440121103713. The reversal of 13440121103711 is 11730112104431.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13440121103711 - 2² = 13440121103707 is a prime.

Together with 13440121103713, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13440121103713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720060551855 + 6720060551856.

It is an arithmetic number, because the mean of its divisors is an integer number (6720060551856).

Almost surely, 2^{13440121103711} is an apocalyptic number.

13440121103711 is a deficient number, since it is larger than the sum of its proper divisors (1).

13440121103711 is an equidigital number, since it uses as much as digits as its factorization.

13440121103711 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 29.

The spelling of 13440121103711 in words is "thirteen trillion, four hundred forty billion, one hundred twenty-one million, one hundred three thousand, seven hundred eleven".