Base | Representation |
---|---|
bin | 1100001110100000100101… |
… | …0001011011101010111111 |
3 | 1202121011202212211222012020 |
4 | 3003220021101123222333 |
5 | 3230224042204414330 |
6 | 44331451510011223 |
7 | 2555153030542551 |
oct | 303501121335277 |
9 | 52534685758166 |
10 | 13443403201215 |
11 | 4313351702619 |
12 | 1611508646b13 |
13 | 766927452c30 |
14 | 3469427574d1 |
15 | 184a61703210 |
hex | c3a0945babf |
13443403201215 has 64 divisors (see below), whose sum is σ = 23793616982016. Its totient is φ = 6440033290752.
The previous prime is 13443403201213. The next prime is 13443403201229. The reversal of 13443403201215 is 51210230434431.
It is not a de Polignac number, because 13443403201215 - 21 = 13443403201213 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13443403201213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2653819 + ... + 5824908.
It is an arithmetic number, because the mean of its divisors is an integer number (371775265344).
Almost surely, 213443403201215 is an apocalyptic number.
13443403201215 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13443403201215 is a deficient number, since it is larger than the sum of its proper divisors (10350213780801).
13443403201215 is a wasteful number, since it uses less digits than its factorization.
13443403201215 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8478968.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 13443403201215 its reverse (51210230434431), we get a palindrome (64653633635646).
The spelling of 13443403201215 in words is "thirteen trillion, four hundred forty-three billion, four hundred three million, two hundred one thousand, two hundred fifteen".
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