13445520011300 has 36 divisors (see below), whose sum is σ = 31421145998676. Its totient is φ = 4964499696000.

The previous prime is 13445520011299. The next prime is 13445520011309. The reversal of 13445520011300 is 311002554431.

It can be written as a sum of positive squares in 6 ways, for example, as 405780736 + 13445114230564 = 20144^2 + 3666758^2 .

It is a super-3 number, since 3×13445520011300³ (a number of 40 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (13445520011309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5171352551 + ... + 5171355150.

Almost surely, 2^{13445520011300} is an apocalyptic number.

13445520011300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13445520011300 is an abundant number, since it is smaller than the sum of its proper divisors (17975625987376).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13445520011300 is a wasteful number, since it uses less digits than its factorization.

13445520011300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10342707728 (or 10342707721 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 13445520011300 its reverse (311002554431), we get a palindrome (13756522565731).

The spelling of 13445520011300 in words is "thirteen trillion, four hundred forty-five billion, five hundred twenty million, eleven thousand, three hundred".