Base | Representation |
---|---|
bin | 10011100100110000000… |
… | …000111011111010100110 |
3 | 11202121000110000000110020 |
4 | 103210300000323322212 |
5 | 134014311330043210 |
6 | 2505535550540010 |
7 | 166116404013126 |
oct | 23446000737246 |
9 | 4677013000406 |
10 | 1345130315430 |
11 | 479514aa5140 |
12 | 198841507606 |
13 | 99acb0047b5 |
14 | 4916725ac86 |
15 | 24ecb005770 |
hex | 1393003bea6 |
1345130315430 has 128 divisors (see below), whose sum is σ = 3623037465600. Its totient is φ = 316747491840.
The previous prime is 1345130315423. The next prime is 1345130315447. The reversal of 1345130315430 is 345130315431.
It is a super-2 number, since 2×13451303154302 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a junction number, because it is equal to n+sod(n) for n = 1345130315391 and 1345130315400.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7221832 + ... + 7405748.
It is an arithmetic number, because the mean of its divisors is an integer number (28304980200).
Almost surely, 21345130315430 is an apocalyptic number.
1345130315430 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 1345130315430, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1811518732800).
1345130315430 is an abundant number, since it is smaller than the sum of its proper divisors (2277907150170).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1345130315430 is a wasteful number, since it uses less digits than its factorization.
1345130315430 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 184574.
The product of its (nonzero) digits is 32400, while the sum is 33.
Subtracting from 1345130315430 its reverse (345130315431), we obtain a palindrome (999999999999).
The spelling of 1345130315430 in words is "one trillion, three hundred forty-five billion, one hundred thirty million, three hundred fifteen thousand, four hundred thirty".
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